by Florin Diacu (First edition, 2000)
Corrections
| page | position | corrected text | comment |
| inside | Integration table - | ``ln|·|'' | not ``ln(·)'' |
| cover | right side of equations | (10 occurrences) | |
| p.10 | 5th line from bottom | ``f(r) = 1/r for r > 0 and f(0) = 0'' | |
| p.11 | Problem 11, line 3 | ``inverse seventh power'' | insert ``inverse'' |
| p.11 | Problem 11, line 4 | ``inverse ninth power'' | insert ``inverse'' |
| p.11 | Problem 11, col. 2, top line | ``fahn der vahls'' | omit extra ``s'' |
| p.33 | Step 5, line 1 | ``c into x in step 2'' | not ``u'' |
| p.34 | Step 5, line 1 | ``function x in step 2'' | not ``u'' |
| p.39 | Problem 10 | ``t2v -3t2'' | sign of exponent |
| p.39 | Problem 16 | ``(t+2)q+t3'' | ``t3'', not ``3t'' |
| p.48 | 2nd para., line 6 | ``101 kg/m3'' | insert ``kg/m3'' |
| p.50 | Problem 33, equation | ``P¢ = kP([P/( n1)]-1)(1-[P/( n2)])-N'' | insert ``P'' |
| p.50 | Problem 34, lines 5-6 | ``amount of glucose present'' | not ``injected'' |
| p.50 | Problem 34, line 9 | ``a differential equation'' | not ``logistic'' |
| p.50 | Problem 36, line 2 | ``force per unit mass'' | insert phrase |
| p.50 | Problem 37, line 2 | ``forces per unit mass'' | insert phrase |
| p.60 | line 2 after Problem 20 | ``through 28, apply the'' | delete phrase |
| p.60 | Problem 26 | ``x¢ = x2ln(t+1)'' | replace equation |
| p.79 | Problem 28, line 1 | ``[0,0.5]'' | change interval |
| p.81 | last line, equation | ``P¢ = kP([P/( n1)]-1)(1-[P/( n2)])-AcosBt'' | insert ``P'' |
| p.91 | Problem 17, line 2 | ``w¢(e) = [3/( Öe)]'' | denominator |
| p.91 | Problem 20, line 2 | ``y¢(1) = 0'' | repeated (delete 1) |
| p.93 | Step 3, line 1 | ``r1 = r2 = -b/2'' | minus |
| p.100 | Problem 20 | ``x¢¢ = -1/2(x¢)2+x¢'' | replace equation |
| p.100 | Problem 27 | ``x¢¢ = 4/tx¢-[6/( t2)]x'' | replace equation |
| p.107 | Line 5 from bottom | ``variable source (as shown...'' | not ``resistor'' |
| p.107 | Line 2 from bottom | ``an electromagnetic force...'' | not ``a resistance...'' |
| p.107 | Last line | ``variance of the source at the...'' | not ``resistor'' |
| p.108 | Line 4 | ``mx¢¢ = Fweight+Felectromagnetic'' | not ``resistance'' |
| p.108 | Line 6 | ``Felectromagnetic'' | not ``resistance'' |
| p.108 | Figure 3.3.1 | ``source'' | not ``resistor'' |
| p.109 | Lines 4-3 before Problems | ``shows that the electromagnetic force'' | delete, replace |
| p.109 | Lines 3-2 before Problems | ``so the bar is pushed'' | delete ``finally'' |
| p.110 | Problem 36, 1st equation | ``x¢¢ = -k/mx¢-[2g/ L]x'' | minus |
| p.110 | Problem 36, 2nd equation | ``x¢¢ = -k/mx¢-[2g/ L]x+[1/ 10]cos8pt'' | minus |
| page | position | corrected text | comment |
| p.121 | Problem 28, line 7 | ``m = 1kg, n = 1/5kg/sec, k = 1N/m, | replace |
| a = 1m, w0 = 1Hz'' | parameters | ||
| p.137 | Applications, line 15 | `` n = 0.1kg/sec'' | add units |
| p.137 | Last paragraph, line 2 | `` n = 0.1kg/sec'' | add units |
| p.137 | Last paragraph, line 2 | ``cords with coef-'' | delete ``damping'' |
| p.141 | Problems, line 2 after (d) | ``t = 0.1 (a,c) or t = 0.05 (b,d)'' | |
| p.142 | Problem 9, line 5 | ``Table 3.6.2'' | not ``3.4.2'' |
| p.142 | Problem 12, line 1 | ``x(0) = x¢(0) = 0.1'' | not ``0'' |
| p.142 | Problem 13, line 1 | ``x¢¢ = -x¢-x'' | replace equation |
| p.142 | Problem 14, line 1 | ``x¢¢ = x¢-x , x(0) = x¢(0) = 1'' | delete p's, change IC |
| p.142 | Problem 15, line 1 | ``x¢¢ = -x¢-x'' | replace equation |
| p.142 | Problem 16, line 1 | ``x¢¢ = 1/tx¢-x/t ,'' | minus (note comma) |
| p.142 | Problem 17, line 1 | ``x¢¢ = -[(e-t)/( t-2)]x¢-[(4t2)/( t2-4)]x+2(1-t)'' | replace equation |
| p.142 | Problem 18, line 1 | ``x¢¢ = [1/( 1-t)]x¢-[x/( 1-t)] ,'' | replace (note comma) |
| p.142 | Problem 18, line 2 | ``[2,10]'' | not ``[2,100]'' |
| p.146 | program,lines 13,14 | ``t=t+h: M:=(M,[t,x]):'' | reverse order |
| p.155 | Problem 15 | ``x¢¢ = x¢+x+cost'' | replace equation |
| p.156 | Problem 21 | ``x¢¢ = 1/4x¢+x+t'' | numerator |
| p.156 | Problem 22 | ``x¢¢ = -1/3x¢-x-t'' | minus |
| p.156 | Problem 27 | ``x¢¢ = tx¢+2x'' | denominator |
| p.156 | Problem 35, line 2 | ``[1,2.5]'' | not ``[1,4]'' |
| p.169 | Problem 30, line 1 | ``Example 9'' | not ``8'' |
| p.169 | Problem 30, lines 2,3,5 | u1, u2, u3 | not x1, x2, x3 |
| p.173 | Proof, line 6 | ``f(t) = c1u+c2v+c3w'' | not ``j(t)'' |
| p.173 | Proof, line 6 | ``solution of (7)'' | not ``(5)'' |
| p.173 | Proof, 3rd last line | ``solution of (7)'' | not ``(5)'' |
| p.187 | Problem 18, line 8 | ``(asinbt+bcosbt)eat'' | 2nd expression |
| p.193 | line 4 | ``(d) a = 1/2, b = -1/2, c = 1'' | change a,b values |
| p.199 | Problem 31, line 3 | ``z¢ = 1/2z'' | change z equation |
| p.199 | Problem 32, line 1 | ``u¢ = 5v'' | change u equation |
| p.199 | Problem 32, line 2 | ``v¢ = -5u+6v'' | change v equation |
| p.199 | Problem 32, line 3 | ``r¢ = 5r'' | change r equation |
| p.199 | Problem 33, line 1 | ``w¢ = -w+r'' | change w equation |
| p.199 | Problem 33, line 2 | ``r¢ = -2w+r'' | change r equation |
| p.199 | Problem 33, line 3 | ``q¢ = -2q'' | change q equation |
| p.199 | Problem 35, line 1 | ``U¢ = -U-2V'' | change U equation |
| p.199 | Problem 35, line 2 | ``V¢ = U-2V'' | change V equation |
| p.199 | Problem 35, line 3 | ``W¢ = -W'' | change W equation |
| p.204 | Equation for In+1 | ``-Qn+1E'' | change last term |
| p.204 | Equation for Qn+1 | ``Qn+h/2(In-Qn+In+1E-Qn+1E)'' | change equation |
| p.207 | Definition 6.1.2, line 2 | ``u¢ = -u-2v'' | delete ``p'' |
| page | position | corrected text | comment |
| p.225 | last line | ``Figure 5.1.1(a)'' | not ``5.1(a)'' |
| p.226 | Example 2, line 5 | ``Figure 5.1.1(b)'' | not ``5.1(b)'' |
| p.240 | Problem 9 | ``y¢ = x+y(1-x2-y2)'' | change last ``+'' to ``-'' |
| p.255 | Example 5, line 6 | ``l2 = iÖ2, l3 = -iÖ2'' | not 2i and -2i |
| p.272 | Problem 18, line 1 | ``into intervals'' | delete ``several'' |
| p.275 | Inverse Transform, lines 8-9 | ``set of continuous functions'' | insert ``continuous'' |
| p.282 | Example 8, last equation | ``4, for t ³ 4,'' | not ``2, for t ³ 4,'' |
| p.347 | Section 2.1, after 29. | ``31. x1 = 1, x2 = -1'' | insert |
| p.348 | Section 2.2, answer 29. | ``11.00 years'' | |
| p.349 | Section 2.3, answer 27. | ``x(t) = ±Ö{[a/( b+ke-2t)]}'' | ``±'' in front |
| p.349 | Section 2.3, answer 39. | ``lnt -2'' | denominator |
| p.354 | Section 2.4, answer 37. | ``1 £ a < 2'' | |
| p.354 | Section 2.5, answer 17. | ``fn = 4åk = 2n(t/2)k[1/ k!]'' | 2 terms wrong |
| p.355 | Section 2.5, answer 21. | ``f1(t) = f2(t) = f3(t) = 1-cost-t'' | |
| p.355 | Section 2.6, answer 9(a). | ``... all n. x(t) = 3 is an equilibrium.'' | |
| p.355 | Section 2.6, 9(b), line 2. | ``x(t) = [(3(1-e-t))/( 3e-t+1)]'' | replace equation |
| p.355 | Section 2.6, 11. | ``(a) 0 (b) 0'' | |
| p.355 | Section 2.6, 13. | ``(a) 0 (b) 0'' | |
| p.357 | Section 3.2, answer 5. | ``[([Ö11])/ 2]'' | replace ``[Ö11]'' twice |
| p.357 | Section 3.2, answer 19. | ``x(t) = -tan-1(t/2)+1'' | minus |
| p.357 | Section 3.2, after 35. | ``39. T = 2pÖ{[(grbox)/( Lrwater)]}'' | insert |
| p.358 | Section 3.4, answer 11. | ``x(t) = A(t)cos[((w+w0)t)/ 2] with | replace |
| A(t) = -[2a/( (w2-w02))]sin(w-w0)t/2'' | |||
| p.365 | Section 3.5, answer 39. | ``perpendicular to the x-axis.'' | not ``at'' |
| p.366 | Section 4.1, answer 15. | ``form identical planes.'' | replace ``two parallel'' |
| p.368 | Section 4.3, answer 13. | ``y(t) = c1eat(acosbt-bsinbt) | insert b's in y |
| +c2eat(asinbt+bcosbt)'' | equation for l1,2 | ||
| p.368 | Section 4.3, answer 19. | ``e-0.0089'' | not ``e-0.089'' |
| p.383 | Section 6.3, answer 11. | ``q(t)'' | not ``Q(t)'' |